What are the solutions to the equation 3y^2=-16y ?

The solutions to the equation 3y^2=-16y are y=0,y=-16/3

Find the zeros of 3y^2=-16y

The zeros of 3y^2=-16y are y=0,y=-16/3

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3 y^{2} = - 16 y

y = 0, y = - \frac{16}{3}

Decimal Notation

y = 0, y = - 5.33333 \dots

Solution steps

3 y^{2} = - 16 y

Move

16 y

to the left side

3 y^{2} + 16 y = 0

Factor

3 y^{2} + 16 y : y (3 y + 16)

y (3 y + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y + 16 = 0

Solve

3 y + 16 = 0 : y = - \frac{16}{3}

The solutions to the quadratic equation are:

y = 0, y = - \frac{16}{3}

(x + 3)^{2} = 121

10 x^{2} = - 20 x + 80

0.5 x^{2} + 2.1 x = 0.3

x^{2} + 2 x + \frac{1}{4} = 0

- 12 x^{2} - 18 x = 0

What are the solutions to the equation 3y^2=-16y ?
The solutions to the equation 3y^2=-16y are y=0,y=-16/3
Find the zeros of 3y^2=-16y
The zeros of 3y^2=-16y are y=0,y=-16/3