What are the solutions to the equation 9x^2-24x+16=2 ?

The solutions to the equation 9x^2-24x+16=2 are x=(4+sqrt(2))/3 ,x=(4-sqrt(2))/3

Find the zeros of 9x^2-24x+16=2

The zeros of 9x^2-24x+16=2 are x=(4+sqrt(2))/3 ,x=(4-sqrt(2))/3

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9 x^{2} - 24 x + 16 = 2

x = \frac{4 + 2}{3}, x = \frac{4 - 2}{3}

Decimal Notation

x = 1.80473 \dots, x = 0.86192 \dots

Solution steps

9 x^{2} - 24 x + 16 = 2

Move

2

to the left side

9 x^{2} - 24 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 14}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 14 = 62

x_{1, 2} = \frac{- ( - 24 ) \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6 2}{2 \cdot 9}, x_{2} = \frac{- ( - 24 ) - 6 2}{2 \cdot 9}

x = \frac{- ( - 24 ) + 6 2}{2 \cdot 9} : \frac{4 + 2}{3}

x = \frac{- ( - 24 ) - 6 2}{2 \cdot 9} : \frac{4 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 2}{3}, x = \frac{4 - 2}{3}

- k - (- 8 k)

1 \leq 1

∣ x - 6 ∣ + 7 \geq - 1

\frac{v}{3} + \frac{v}{4} = 7

- 2 \geq \frac{x}{2}

What are the solutions to the equation 9x^2-24x+16=2 ?
The solutions to the equation 9x^2-24x+16=2 are x=(4+sqrt(2))/3 ,x=(4-sqrt(2))/3
Find the zeros of 9x^2-24x+16=2
The zeros of 9x^2-24x+16=2 are x=(4+sqrt(2))/3 ,x=(4-sqrt(2))/3