What are the solutions to the equation X^2-11X+24=0 ?

The solutions to the equation X^2-11X+24=0 are X=8,X=3

Find the zeros of X^2-11X+24=0

The zeros of X^2-11X+24=0 are X=8,X=3

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X^{2} - 11 X + 24 = 0

X = 8, X = 3

Solution steps

X^{2} - 11 X + 24 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

X_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, X_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

X = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

X = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

X = 8, X = 3

\frac{x ^{2}}{3} = 48

- y^{2} + 21 y - 104 = 0

4 c^{2} - 2 c = 23

2 x^{2} + 7 x - 4 = 0

2 x^{2} + 5 x - 168 = 0

What are the solutions to the equation X^2-11X+24=0 ?
The solutions to the equation X^2-11X+24=0 are X=8,X=3
Find the zeros of X^2-11X+24=0
The zeros of X^2-11X+24=0 are X=8,X=3