What are the solutions to the equation k^2+12k+36=0 ?

The solutions to the equation k^2+12k+36=0 are k=-6

Find the zeros of k^2+12k+36=0

The zeros of k^2+12k+36=0 are k=-6

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k^{2} + 12 k + 36 = 0

k = - 6

Solution steps

k^{2} + 12 k + 36 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 36 = 0

k_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 1}

k = \frac{- 12}{2 \cdot 1}

\frac{- 12}{2 \cdot 1} = - 6

k = - 6

The solution to the quadratic equation is:

k = - 6

6 + x - x^{2} = 0

t^{2} - 9 t + 18 = 0

x^{2} + 7 x + 12 = 0

- 11 + 4 x^{2} = - 7 x - 2

5 x^{2} - 2 - x^{2} = 3 x^{2} - 3

What are the solutions to the equation k^2+12k+36=0 ?
The solutions to the equation k^2+12k+36=0 are k=-6
Find the zeros of k^2+12k+36=0
The zeros of k^2+12k+36=0 are k=-6