What are the solutions to the equation y^2+2=0 ?

The solutions to the equation y^2+2=0 are y=sqrt(2)i,y=-sqrt(2)i

Find the zeros of y^2+2=0

The zeros of y^2+2=0 are y=sqrt(2)i,y=-sqrt(2)i

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y^{2} + 2 = 0

y = 2 i, y = - 2 i

Solution steps

y^{2} + 2 = 0

Move

2

to the right side

y^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 2, y = - - 2

- 2 = 2 i

- - 2 = - 2 i

y = 2 i, y = - 2 i

- 15 x (x - 8) = 0

x, z = 4 x^{2} + 3 y^{2}

y, x = y^{2} + z^{2}

x^{2} - 4 \cdot x + 3 = 0

- 2 x^{2} = x - 3

What are the solutions to the equation y^2+2=0 ?
The solutions to the equation y^2+2=0 are y=sqrt(2)i,y=-sqrt(2)i
Find the zeros of y^2+2=0
The zeros of y^2+2=0 are y=sqrt(2)i,y=-sqrt(2)i