What are the solutions to the equation 7x^2+6=13 ?

The solutions to the equation 7x^2+6=13 are x=1,x=-1

Find the zeros of 7x^2+6=13

The zeros of 7x^2+6=13 are x=1,x=-1

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7 x^{2} + 6 = 13

x = 1, x = - 1

Solution steps

7 x^{2} + 6 = 13

Move

6

to the right side

7 x^{2} = 7

Divide both sides by

7

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(3 y - 1)^{2} = 0

3 u^{2} = 18 u - 6

x^{2} - 3 x - 6

x + 5 x^{2} + 3 = 3

x^{2} - x = \frac{3}{4}

What are the solutions to the equation 7x^2+6=13 ?
The solutions to the equation 7x^2+6=13 are x=1,x=-1
Find the zeros of 7x^2+6=13
The zeros of 7x^2+6=13 are x=1,x=-1