What are the solutions to the equation s^2+3s-4=0 ?

The solutions to the equation s^2+3s-4=0 are s=1,s=-4

Find the zeros of s^2+3s-4=0

The zeros of s^2+3s-4=0 are s=1,s=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} + 3 s - 4 = 0

s = 1, s = - 4

Solution steps

s^{2} + 3 s - 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

s_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 3 + 5}{2 \cdot 1}, s_{2} = \frac{- 3 - 5}{2 \cdot 1}

s = \frac{- 3 + 5}{2 \cdot 1} : 1

s = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

s = 1, s = - 4

2 x^{2} + 8 x - 5

- x^{2} + 3 x - 10 = 0

x, ln (y) = x^{2} y

- a^{2} + 9 a - 18 = 0

0 = x^{2} - 6

What are the solutions to the equation s^2+3s-4=0 ?
The solutions to the equation s^2+3s-4=0 are s=1,s=-4
Find the zeros of s^2+3s-4=0
The zeros of s^2+3s-4=0 are s=1,s=-4