What are the solutions to the equation 26=6+37t-16t^2 ?

The solutions to the equation 26=6+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)

Find the zeros of 26=6+37t-16t^2

The zeros of 26=6+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)

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26 = 6 + 37 t - 16 t^{2}

t = \frac{37 - 89}{32}, t = \frac{37 + 89}{32}

Decimal Notation

t = 0.86143 \dots, t = 1.45106 \dots

Solution steps

26 = 6 + 37 t - 16 t^{2}

Switch sides

6 + 37 t - 16 t^{2} = 26

Move

26

to the left side

- 16 t^{2} + 37 t - 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 37 \pm 3 7 ^{2} - 4 ( - 16 ) ( - 20 )}{2 ( - 16 )}

3 7^{2} - 4 (- 16) (- 20) = 89

t_{1, 2} = \frac{- 37 \pm 89}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 37 + 89}{2 ( - 16 )}, t_{2} = \frac{- 37 - 89}{2 ( - 16 )}

t = \frac{- 37 + 89}{2 ( - 16 )} : \frac{37 - 89}{32}

t = \frac{- 37 - 89}{2 ( - 16 )} : \frac{37 + 89}{32}

The solutions to the quadratic equation are:

t = \frac{37 - 89}{32}, t = \frac{37 + 89}{32}

7 x^{2} + 2 x + 1 = 0

x^{2} = - 4 x + 8

3 x^{2} - 2 = 190

5 (x - 1)^{2} + 7 = 127

4 - 72 x^{2} = 0

What are the solutions to the equation 26=6+37t-16t^2 ?
The solutions to the equation 26=6+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)
Find the zeros of 26=6+37t-16t^2
The zeros of 26=6+37t-16t^2 are t=(37-sqrt(89))/(32),t=(37+sqrt(89))/(32)