What are the solutions to the equation (4x+9)^2=25 ?

The solutions to the equation (4x+9)^2=25 are x=-1,x=-7/2

Find the zeros of (4x+9)^2=25

The zeros of (4x+9)^2=25 are x=-1,x=-7/2

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(4 x + 9)^{2} = 25

x = - 1, x = - \frac{7}{2}

Decimal Notation

x = - 1, x = - 3.5

Solution steps

(4 x + 9)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 9 = 25 : x = - 1

Solve

4 x + 9 = - 25 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{2}

(x + 10) (x - 5) = 0

x^{2} + 5 x = 126

x^{2} - 4 x + 27 = 0

x, x^{2} - 8 x + 15 = 0

y^{2} - 10 y + 16 = 0

What are the solutions to the equation (4x+9)^2=25 ?
The solutions to the equation (4x+9)^2=25 are x=-1,x=-7/2
Find the zeros of (4x+9)^2=25
The zeros of (4x+9)^2=25 are x=-1,x=-7/2