What are the solutions to the equation 9x^2+8x-5=3x^2 ?

The solutions to the equation 9x^2+8x-5=3x^2 are x=(-4+sqrt(46))/6 ,x=-(4+sqrt(46))/6

Find the zeros of 9x^2+8x-5=3x^2

The zeros of 9x^2+8x-5=3x^2 are x=(-4+sqrt(46))/6 ,x=-(4+sqrt(46))/6

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9 x^{2} + 8 x - 5 = 3 x^{2}

x = \frac{- 4 + 46}{6}, x = - \frac{4 + 46}{6}

Decimal Notation

x = 0.46372 \dots, x = - 1.79705 \dots

Solution steps

9 x^{2} + 8 x - 5 = 3 x^{2}

Move

3 x^{2}

to the left side

6 x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

8^{2} - 4 \cdot 6 (- 5) = 246

x_{1, 2} = \frac{- 8 \pm 2 46}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 8 + 2 46}{2 \cdot 6}, x_{2} = \frac{- 8 - 2 46}{2 \cdot 6}

x = \frac{- 8 + 2 46}{2 \cdot 6} : \frac{- 4 + 46}{6}

x = \frac{- 8 - 2 46}{2 \cdot 6} : - \frac{4 + 46}{6}

The solutions to the quadratic equation are:

x = \frac{- 4 + 46}{6}, x = - \frac{4 + 46}{6}

y, x^{3} y^{2} - 6 x^{2} = 3 y^{2} - 9 x

1 0^{2} = x^{2} + (x + 2)^{2}

3 x^{2} + 12 x + 10 = 0

7 x^{2} + 9 x + 1 = 0

(x - 1)^{2} = 6

What are the solutions to the equation 9x^2+8x-5=3x^2 ?
The solutions to the equation 9x^2+8x-5=3x^2 are x=(-4+sqrt(46))/6 ,x=-(4+sqrt(46))/6
Find the zeros of 9x^2+8x-5=3x^2
The zeros of 9x^2+8x-5=3x^2 are x=(-4+sqrt(46))/6 ,x=-(4+sqrt(46))/6