What are the solutions to the equation 2n^2+10n-10=0 ?

The solutions to the equation 2n^2+10n-10=0 are n=(-5+3sqrt(5))/2 ,n=-(5+3sqrt(5))/2

Find the zeros of 2n^2+10n-10=0

The zeros of 2n^2+10n-10=0 are n=(-5+3sqrt(5))/2 ,n=-(5+3sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 n^{2} + 10 n - 10 = 0

n = \frac{- 5 + 3 5}{2}, n = - \frac{5 + 3 5}{2}

Decimal Notation

n = 0.85410 \dots, n = - 5.85410 \dots

Solution steps

2 n^{2} + 10 n - 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 10) = 65

n_{1, 2} = \frac{- 10 \pm 6 5}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 10 + 6 5}{2 \cdot 2}, n_{2} = \frac{- 10 - 6 5}{2 \cdot 2}

n = \frac{- 10 + 6 5}{2 \cdot 2} : \frac{- 5 + 3 5}{2}

n = \frac{- 10 - 6 5}{2 \cdot 2} : - \frac{5 + 3 5}{2}

The solutions to the quadratic equation are:

n = \frac{- 5 + 3 5}{2}, n = - \frac{5 + 3 5}{2}

b (b + 7) = 0

a^{2} - 3 a + 4 = 0

D, (D + 1)^{2} y = 0

y^{2} - 29 y + 168 = 0

8 (p - 2)^{2} - 8 = - 97

What are the solutions to the equation 2n^2+10n-10=0 ?
The solutions to the equation 2n^2+10n-10=0 are n=(-5+3sqrt(5))/2 ,n=-(5+3sqrt(5))/2
Find the zeros of 2n^2+10n-10=0
The zeros of 2n^2+10n-10=0 are n=(-5+3sqrt(5))/2 ,n=-(5+3sqrt(5))/2