What are the solutions to the equation x^2+2x=-15 ?

The solutions to the equation x^2+2x=-15 are x=-1+sqrt(14)i,x=-1-sqrt(14)i

Find the zeros of x^2+2x=-15

The zeros of x^2+2x=-15 are x=-1+sqrt(14)i,x=-1-sqrt(14)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x = - 15

x = - 1 + 14 i, x = - 1 - 14 i

Solution steps

x^{2} + 2 x = - 15

Move

15

to the left side

x^{2} + 2 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 15 : 214 i

x_{1, 2} = \frac{- 2 \pm 2 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 14 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 14 i}{2 \cdot 1}

x = \frac{- 2 + 2 14 i}{2 \cdot 1} : - 1 + 14 i

x = \frac{- 2 - 2 14 i}{2 \cdot 1} : - 1 - 14 i

The solutions to the quadratic equation are:

x = - 1 + 14 i, x = - 1 - 14 i

x^{2} - 1 = 0

a^{2} = 2 a + 3

x^{2} - 9 x + 14 = 0

X^{2} - 16 X + 64 = 0

k^{2} + k - 6 = 0

What are the solutions to the equation x^2+2x=-15 ?
The solutions to the equation x^2+2x=-15 are x=-1+sqrt(14)i,x=-1-sqrt(14)i
Find the zeros of x^2+2x=-15
The zeros of x^2+2x=-15 are x=-1+sqrt(14)i,x=-1-sqrt(14)i