What are the solutions to the equation -x^2+2x+7=0 ?

The solutions to the equation -x^2+2x+7=0 are x=1-2sqrt(2),x=1+2sqrt(2)

Find the zeros of -x^2+2x+7=0

The zeros of -x^2+2x+7=0 are x=1-2sqrt(2),x=1+2sqrt(2)

Popular >

- x^{2} + 2 x + 7 = 0

x = 1 - 22, x = 1 + 22

Decimal

x = - 1.82842 \dots, x = 3.82842 \dots

Solution steps

- x^{2} + 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 7 = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 4 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4 2}{2 ( - 1 )}

x = \frac{- 2 + 4 2}{2 ( - 1 )} : 1 - 22

x = \frac{- 2 - 4 2}{2 ( - 1 )} : 1 + 22

The solutions to the quadratic equation are:

x = 1 - 22, x = 1 + 22

\frac{x ^{2}}{3} - \frac{x ( x - 1 )}{4} - 1 = (x^{2} - 1)

3 x^{2} - 1 = 4 λ x, - y = 2 λ x, x^{2} + y^{2} = 1

2 a x^{2} + (3 a - 1) x + a + b = 0

x^{2} + 2 x + 7 = x + 7

- x^{2} + 2 x + 9 = 0

What are the solutions to the equation -x^2+2x+7=0 ?
The solutions to the equation -x^2+2x+7=0 are x=1-2sqrt(2),x=1+2sqrt(2)
Find the zeros of -x^2+2x+7=0
The zeros of -x^2+2x+7=0 are x=1-2sqrt(2),x=1+2sqrt(2)