What are the solutions to the equation (x-2)^2-1=0 ?

The solutions to the equation (x-2)^2-1=0 are x=3,x=1

Find the zeros of (x-2)^2-1=0

The zeros of (x-2)^2-1=0 are x=3,x=1

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(x - 2)^{2} - 1 = 0

x = 3, x = 1

Solution steps

(x - 2)^{2} - 1 = 0

Move

1

to the right side

(x - 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 1 : x = 3

Solve

x - 2 = - 1 : x = 1

The solutions to the quadratic equation are:

x = 3, x = 1

2 + \frac{3}{1 + \frac{5}{2}}

\frac{330 π}{180}

- \frac{2}{27} + \frac{1}{2}

\frac{2 3}{8}

15 + x \leq 0

What are the solutions to the equation (x-2)^2-1=0 ?
The solutions to the equation (x-2)^2-1=0 are x=3,x=1
Find the zeros of (x-2)^2-1=0
The zeros of (x-2)^2-1=0 are x=3,x=1