What are the solutions to the equation w^2-8w+15=0 ?

The solutions to the equation w^2-8w+15=0 are w=5,w=3

Find the zeros of w^2-8w+15=0

The zeros of w^2-8w+15=0 are w=5,w=3

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w^{2} - 8 w + 15 = 0

w = 5, w = 3

Solution steps

w^{2} - 8 w + 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

w_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, w_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

w = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

w = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

w = 5, w = 3

t, f (6 - t) = 3 - 5 (6 - t) - 2 (6 - t)^{2}

t, s = 32 t - 16 t^{2}

(m + 3) x^{2} - (2 m - 5) x + 2 m - 10 = 0

r^{2} + 200 r + 10000 = 0

3 0^{2} + 4 0^{2} = x^{2}

What are the solutions to the equation w^2-8w+15=0 ?
The solutions to the equation w^2-8w+15=0 are w=5,w=3
Find the zeros of w^2-8w+15=0
The zeros of w^2-8w+15=0 are w=5,w=3