What are the solutions to the equation 4(x+2)^2=16 ?

The solutions to the equation 4(x+2)^2=16 are x=0,x=-4

Find the zeros of 4(x+2)^2=16

The zeros of 4(x+2)^2=16 are x=0,x=-4

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4 (x + 2)^{2} = 16

x = 0, x = - 4

Solution steps

4 (x + 2)^{2} = 16

Divide both sides by

4

(x + 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 4 : x = 0

Solve

x + 2 = - 4 : x = - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

z^{2} - 100 = 0

9 x^{2} - 60 x + 75 = 0

x^{2} - 5 x - 9

x^{2} - 5 x + 4

2 x^{2} - 2 x - 11 = 0

What are the solutions to the equation 4(x+2)^2=16 ?
The solutions to the equation 4(x+2)^2=16 are x=0,x=-4
Find the zeros of 4(x+2)^2=16
The zeros of 4(x+2)^2=16 are x=0,x=-4