What are the solutions to the equation -3x^2+16x-10=0 ?

The solutions to the equation -3x^2+16x-10=0 are x=(8-sqrt(34))/3 ,x=(8+sqrt(34))/3

Find the zeros of -3x^2+16x-10=0

The zeros of -3x^2+16x-10=0 are x=(8-sqrt(34))/3 ,x=(8+sqrt(34))/3

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- 3 x^{2} + 16 x - 10 = 0

x = \frac{8 - 34}{3}, x = \frac{8 + 34}{3}

Decimal Notation

x = 0.72301 \dots, x = 4.61031 \dots

Solution steps

- 3 x^{2} + 16 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 3 ) ( - 10 )}{2 ( - 3 )}

1 6^{2} - 4 (- 3) (- 10) = 234

x_{1, 2} = \frac{- 16 \pm 2 34}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 16 + 2 34}{2 ( - 3 )}, x_{2} = \frac{- 16 - 2 34}{2 ( - 3 )}

x = \frac{- 16 + 2 34}{2 ( - 3 )} : \frac{8 - 34}{3}

x = \frac{- 16 - 2 34}{2 ( - 3 )} : \frac{8 + 34}{3}

The solutions to the quadratic equation are:

x = \frac{8 - 34}{3}, x = \frac{8 + 34}{3}

(x - \frac{3}{2})^{2} = \frac{25}{4}

x^{2} - 25 x + 75 = 0

x^{2} - 8 x + 13

x^{2} - 8 x + 11

4 x^{2} + 3 x = 10

What are the solutions to the equation -3x^2+16x-10=0 ?
The solutions to the equation -3x^2+16x-10=0 are x=(8-sqrt(34))/3 ,x=(8+sqrt(34))/3
Find the zeros of -3x^2+16x-10=0
The zeros of -3x^2+16x-10=0 are x=(8-sqrt(34))/3 ,x=(8+sqrt(34))/3