What are the solutions to the equation f^2+6f+9=0 ?

The solutions to the equation f^2+6f+9=0 are f=-3

Find the zeros of f^2+6f+9=0

The zeros of f^2+6f+9=0 are f=-3

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f^{2} + 6 f + 9 = 0

f = - 3

Solution steps

f^{2} + 6 f + 9 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

f_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

f = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

f = - 3

The solution to the quadratic equation is:

f = - 3

x^{2} + 3 x - 18

x^{2} - 11 x - 30 = 0

x^{2} - 5 x = - 5

- x^{2} - 9 x - 1 = 0

4 x^{2} + 11 x = 3 x - 10

What are the solutions to the equation f^2+6f+9=0 ?
The solutions to the equation f^2+6f+9=0 are f=-3
Find the zeros of f^2+6f+9=0
The zeros of f^2+6f+9=0 are f=-3