What are the solutions to the equation x^2-4x+4=64 ?

The solutions to the equation x^2-4x+4=64 are x=10,x=-6

Find the zeros of x^2-4x+4=64

The zeros of x^2-4x+4=64 are x=10,x=-6

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x^{2} - 4 x + 4 = 64

x = 10, x = - 6

Solution steps

x^{2} - 4 x + 4 = 64

Move

64

to the left side

x^{2} - 4 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 60) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 1}

x = \frac{- ( - 4 ) + 16}{2 \cdot 1} : 10

x = \frac{- ( - 4 ) - 16}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 10, x = - 6

x, 25 x^{2} + 15 y^{2} - 3 x - 7 y + 10 = 0

X^{2} - 6 X + 5 = 0

x^{2} - 11 x + 18 = 0

x, x^{2} + 2 x y - y^{2} = 1

6 y^{2} + y - 1 = 0

What are the solutions to the equation x^2-4x+4=64 ?
The solutions to the equation x^2-4x+4=64 are x=10,x=-6
Find the zeros of x^2-4x+4=64
The zeros of x^2-4x+4=64 are x=10,x=-6