What are the solutions to the equation 8y^2-30y+27=22 ?

The solutions to the equation 8y^2-30y+27=22 are y=(15+sqrt(185))/8 ,y=(15-sqrt(185))/8

Find the zeros of 8y^2-30y+27=22

The zeros of 8y^2-30y+27=22 are y=(15+sqrt(185))/8 ,y=(15-sqrt(185))/8

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8 y^{2} - 30 y + 27 = 22

y = \frac{15 + 185}{8}, y = \frac{15 - 185}{8}

Decimal Notation

y = 3.57518 \dots, y = 0.17481 \dots

Solution steps

8 y^{2} - 30 y + 27 = 22

Move

22

to the left side

8 y^{2} - 30 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

(- 30)^{2} - 4 \cdot 8 \cdot 5 = 2185

y_{1, 2} = \frac{- ( - 30 ) \pm 2 185}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 30 ) + 2 185}{2 \cdot 8}, y_{2} = \frac{- ( - 30 ) - 2 185}{2 \cdot 8}

y = \frac{- ( - 30 ) + 2 185}{2 \cdot 8} : \frac{15 + 185}{8}

y = \frac{- ( - 30 ) - 2 185}{2 \cdot 8} : \frac{15 - 185}{8}

The solutions to the quadratic equation are:

y = \frac{15 + 185}{8}, y = \frac{15 - 185}{8}

2 x (x + 4) = 0

x^{2} + 10 x - 23 = 0

x^{2} - 4 x + 12 = 0

x^{2} + x - 6 x = 0

x^{2} - 20 x + 83 = 0

What are the solutions to the equation 8y^2-30y+27=22 ?
The solutions to the equation 8y^2-30y+27=22 are y=(15+sqrt(185))/8 ,y=(15-sqrt(185))/8
Find the zeros of 8y^2-30y+27=22
The zeros of 8y^2-30y+27=22 are y=(15+sqrt(185))/8 ,y=(15-sqrt(185))/8