What are the solutions to the equation 0=x^2-15x+54 ?

The solutions to the equation 0=x^2-15x+54 are x=9,x=6

Find the zeros of 0=x^2-15x+54

The zeros of 0=x^2-15x+54 are x=9,x=6

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0 = x^{2} - 15 x + 54

x = 9, x = 6

Solution steps

0 = x^{2} - 15 x + 54

Switch sides

x^{2} - 15 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

x = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

x = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 9, x = 6

5 x^{2} - 35 + 60 = 0

4 k (k + 14) = 14

50 - x^{2} = 0

5 x^{2} - 16 x - 253 = 4 x + 7

x (5 x - 6) = 11

What are the solutions to the equation 0=x^2-15x+54 ?
The solutions to the equation 0=x^2-15x+54 are x=9,x=6
Find the zeros of 0=x^2-15x+54
The zeros of 0=x^2-15x+54 are x=9,x=6