What are the solutions to the equation (3k+2)^2=49 ?

The solutions to the equation (3k+2)^2=49 are k= 5/3 ,k=-3

Find the zeros of (3k+2)^2=49

The zeros of (3k+2)^2=49 are k= 5/3 ,k=-3

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(3 k + 2)^{2} = 49

k = \frac{5}{3}, k = - 3

Decimal Notation

k = 1.66666 \dots, k = - 3

Solution steps

(3 k + 2)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 k + 2 = 49 : k = \frac{5}{3}

Solve

3 k + 2 = - 49 : k = - 3

The solutions to the quadratic equation are:

k = \frac{5}{3}, k = - 3

x, 615 + x^{2} = 2^{y}

2 x^{2} + 11 x - 15 = 0

3 y^{2} = - 4 y + 16

(x - 8)^{2} = 44

6 x - x^{2} - 8 = 0

What are the solutions to the equation (3k+2)^2=49 ?
The solutions to the equation (3k+2)^2=49 are k= 5/3 ,k=-3
Find the zeros of (3k+2)^2=49
The zeros of (3k+2)^2=49 are k= 5/3 ,k=-3