What are the solutions to the equation 6z^2+13z+6=0 ?

The solutions to the equation 6z^2+13z+6=0 are z=-2/3 ,z=-3/2

Find the zeros of 6z^2+13z+6=0

The zeros of 6z^2+13z+6=0 are z=-2/3 ,z=-3/2

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6 z^{2} + 13 z + 6 = 0

z = - \frac{2}{3}, z = - \frac{3}{2}

Decimal Notation

z = - 0.66666 \dots, z = - 1.5

Solution steps

6 z^{2} + 13 z + 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 \cdot 6 = 5

z_{1, 2} = \frac{- 13 \pm 5}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- 13 + 5}{2 \cdot 6}, z_{2} = \frac{- 13 - 5}{2 \cdot 6}

z = \frac{- 13 + 5}{2 \cdot 6} : - \frac{2}{3}

z = \frac{- 13 - 5}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

z = - \frac{2}{3}, z = - \frac{3}{2}

4 u^{2} - 5 u + 1 = 0

6 x = 4 - x^{2}

\frac{( 3 x ) ^{2}}{8 + 2} = 20

- 192 x^{2} - 192 x - 48 = 0

x^{2} - 20 x + 104 = 8

What are the solutions to the equation 6z^2+13z+6=0 ?
The solutions to the equation 6z^2+13z+6=0 are z=-2/3 ,z=-3/2
Find the zeros of 6z^2+13z+6=0
The zeros of 6z^2+13z+6=0 are z=-2/3 ,z=-3/2