What are the solutions to the equation x^2+12x+38=0 ?

The solutions to the equation x^2+12x+38=0 are x=-6+sqrt(2)i,x=-6-sqrt(2)i

Find the zeros of x^2+12x+38=0

The zeros of x^2+12x+38=0 are x=-6+sqrt(2)i,x=-6-sqrt(2)i

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x^{2} + 12 x + 38 = 0

x = - 6 + 2 i, x = - 6 - 2 i

Solution steps

x^{2} + 12 x + 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 38}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 38 : 22 i

x_{1, 2} = \frac{- 12 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 2 i}{2 \cdot 1}

x = \frac{- 12 + 2 2 i}{2 \cdot 1} : - 6 + 2 i

x = \frac{- 12 - 2 2 i}{2 \cdot 1} : - 6 - 2 i

The solutions to the quadratic equation are:

x = - 6 + 2 i, x = - 6 - 2 i

- 4 x^{2} = - 36

4 x^{2} - 211 = - 15

x, 4 x^{2} + k x + 1 = 0

2 n^{2} - 9 = 119

- 5 x^{2} + 7 x = 0

What are the solutions to the equation x^2+12x+38=0 ?
The solutions to the equation x^2+12x+38=0 are x=-6+sqrt(2)i,x=-6-sqrt(2)i
Find the zeros of x^2+12x+38=0
The zeros of x^2+12x+38=0 are x=-6+sqrt(2)i,x=-6-sqrt(2)i