What are the solutions to the equation s^2-4s-5=0 ?

The solutions to the equation s^2-4s-5=0 are s=5,s=-1

Find the zeros of s^2-4s-5=0

The zeros of s^2-4s-5=0 are s=5,s=-1

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s^{2} - 4 s - 5 = 0

s = 5, s = - 1

Solution steps

s^{2} - 4 s - 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

s_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

s = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

s = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

s = 5, s = - 1

x^{2} - 12 x + 37

0 = 2 x^{2} + x - 1

8 x^{2} = 3 x + 6

y^{2} - 3 y + 15 = 0

x, \frac{1}{3} y - x^{2} + 2 x = - 5

What are the solutions to the equation s^2-4s-5=0 ?
The solutions to the equation s^2-4s-5=0 are s=5,s=-1
Find the zeros of s^2-4s-5=0
The zeros of s^2-4s-5=0 are s=5,s=-1