What are the solutions to the equation x^2+192=0 ?

The solutions to the equation x^2+192=0 are x=8sqrt(3)i,x=-8sqrt(3)i

Find the zeros of x^2+192=0

The zeros of x^2+192=0 are x=8sqrt(3)i,x=-8sqrt(3)i

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x^{2} + 192 = 0

x = 83 i, x = - 83 i

Solution steps

x^{2} + 192 = 0

Move

192

to the right side

x^{2} = - 192

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 192, x = - - 192

- 192 = 83 i

- - 192 = - 83 i

x = 83 i, x = - 83 i

y, y^{2} + z^{2} = 0

(s - 1)^{2} = 0

224 - 24 q + 1.5 q^{2} = 0

4 + 20 x^{2} + 8 x = 0

- 4 x^{2} - 7 x + 9

What are the solutions to the equation x^2+192=0 ?
The solutions to the equation x^2+192=0 are x=8sqrt(3)i,x=-8sqrt(3)i
Find the zeros of x^2+192=0
The zeros of x^2+192=0 are x=8sqrt(3)i,x=-8sqrt(3)i