What are the solutions to the equation 3p^2+1=-43 ?

The solutions to the equation 3p^2+1=-43 are p=(2sqrt(11))/(sqrt(3))i,p=-(2sqrt(11))/(sqrt(3))i

Find the zeros of 3p^2+1=-43

The zeros of 3p^2+1=-43 are p=(2sqrt(11))/(sqrt(3))i,p=-(2sqrt(11))/(sqrt(3))i

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3 p^{2} + 1 = - 43

p = \frac{2 11}{3} i, p = - \frac{2 11}{3} i

Solution steps

3 p^{2} + 1 = - 43

Move

1

to the right side

3 p^{2} = - 44

Divide both sides by

3

p^{2} = - \frac{44}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - \frac{44}{3}, p = - - \frac{44}{3}

- \frac{44}{3} = \frac{2 11}{3} i

- - \frac{44}{3} = - \frac{2 11}{3} i

p = \frac{2 11}{3} i, p = - \frac{2 11}{3} i

2 x^{2} - x

\frac{263}{160} \frac{A ^{2}}{2} \cdot 4 \cdot 1 0^{- 7} = 5 \cdot 1 0^{- 6}

6 x^{2} - 10 x + 1 = 0

6 y^{2} + 2 = - y

s^{2} + s - 1

What are the solutions to the equation 3p^2+1=-43 ?
The solutions to the equation 3p^2+1=-43 are p=(2sqrt(11))/(sqrt(3))i,p=-(2sqrt(11))/(sqrt(3))i
Find the zeros of 3p^2+1=-43
The zeros of 3p^2+1=-43 are p=(2sqrt(11))/(sqrt(3))i,p=-(2sqrt(11))/(sqrt(3))i