What are the solutions to the equation 1/8 x^2+x+2=0 ?

The solutions to the equation 1/8 x^2+x+2=0 are x=-4

Find the zeros of 1/8 x^2+x+2=0

The zeros of 1/8 x^2+x+2=0 are x=-4

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\frac{1}{8} x^{2} + x + 2 = 0

x = - 4

Solution steps

\frac{1}{8} x^{2} + x + 2 = 0

Multiply both sides by

8

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

\frac{x ^{2}}{2} = \frac{1}{6} + \frac{x}{12}

x^{2} - 2 x + \frac{1}{2} = 0

4 x^{2} - 2 x + 2 = 0

x^{2} - 16 x - 192 = 0

3 y^{2} - 6 y + 0 = 0

What are the solutions to the equation 1/8 x^2+x+2=0 ?
The solutions to the equation 1/8 x^2+x+2=0 are x=-4
Find the zeros of 1/8 x^2+x+2=0
The zeros of 1/8 x^2+x+2=0 are x=-4