What is -pi/2 <7x-pi< pi/2 ?

The solution to -pi/2 <7x-pi< pi/2 is pi/(14)<x<(3pi)/(14)

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-pi/2 <7x-pi< pi/2

- \frac{π}{2} < 7 x - π < \frac{π}{2}

\frac{π}{14} < x < \frac{3 π}{14}

Interval Notation

(\frac{π}{14}, \frac{3 π}{14})

Decimal Notation

0.22439 \dots < x < 0.67319 \dots

Solution steps

- \frac{π}{2} < 7 x - π < \frac{π}{2}

a < u < b

then

a < u and u < b

- \frac{π}{2} < 7 x - π and 7 x - π < \frac{π}{2}

- \frac{π}{2} < 7 x - π : x > \frac{π}{14}

7 x - π < \frac{π}{2} : x < \frac{3 π}{14}

Combine the intervals

x > \frac{π}{14} and x < \frac{3 π}{14}

Merge Overlapping Intervals

\frac{π}{14} < x < \frac{3 π}{14}

n^{2} - n

\frac{96}{8}

\frac{1}{4} + \frac{1}{2} - \frac{1}{8}

28 x y + 32 x^{2} - 49 y - 56 x

\frac{9 ^{- 3}}{3 ^{- 8}}

What is -pi/2 <7x-pi< pi/2 ?
The solution to -pi/2 <7x-pi< pi/2 is pi/(14)<x<(3pi)/(14)