What are the solutions to the equation 25p^2+70p+49=0 ?

The solutions to the equation 25p^2+70p+49=0 are p=-7/5

Find the zeros of 25p^2+70p+49=0

The zeros of 25p^2+70p+49=0 are p=-7/5

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25 p^{2} + 70 p + 49 = 0

p = - \frac{7}{5}

Decimal Notation

p = - 1.4

Solution steps

25 p^{2} + 70 p + 49 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 25 \cdot 49}{2 \cdot 25}

7 0^{2} - 4 \cdot 25 \cdot 49 = 0

p_{1, 2} = \frac{- 70 \pm 0}{2 \cdot 25}

p = \frac{- 70}{2 \cdot 25}

\frac{- 70}{2 \cdot 25} = - \frac{7}{5}

p = - \frac{7}{5}

The solution to the quadratic equation is:

p = - \frac{7}{5}

- 0.2 x^{2} + 1.6 x

m^{2} = 4 m - 3

x^{2} + 2 x + c

(x - 1)^{2} = 18

7 - 3 x^{2} = 301

What are the solutions to the equation 25p^2+70p+49=0 ?
The solutions to the equation 25p^2+70p+49=0 are p=-7/5
Find the zeros of 25p^2+70p+49=0
The zeros of 25p^2+70p+49=0 are p=-7/5