What are the solutions to the equation 25^2+4y^2=100 ?

The solutions to the equation 25^2+4y^2=100 are y=(5sqrt(21))/2 i,y=-(5sqrt(21))/2 i

Find the zeros of 25^2+4y^2=100

The zeros of 25^2+4y^2=100 are y=(5sqrt(21))/2 i,y=-(5sqrt(21))/2 i

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2 5^{2} + 4 y^{2} = 100

y = \frac{5 21}{2} i, y = - \frac{5 21}{2} i

Solution steps

2 5^{2} + 4 y^{2} = 100

Move

2 5^{2}

to the right side

4 y^{2} = - 525

Divide both sides by

4

y^{2} = - \frac{525}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{525}{4}, y = - - \frac{525}{4}

- \frac{525}{4} = \frac{5 21}{2} i

- - \frac{525}{4} = - \frac{5 21}{2} i

y = \frac{5 21}{2} i, y = - \frac{5 21}{2} i

5 x^{2} + 25 x + 20 = 0

y^{2} + 4 y - 32 = 0

4 x^{2} + 6 x - 12 = 0

x^{2} + (x + 6)^{2} = 4 8^{2}

s^{2} + 0.2 s + 1 = 0

What are the solutions to the equation 25^2+4y^2=100 ?
The solutions to the equation 25^2+4y^2=100 are y=(5sqrt(21))/2 i,y=-(5sqrt(21))/2 i
Find the zeros of 25^2+4y^2=100
The zeros of 25^2+4y^2=100 are y=(5sqrt(21))/2 i,y=-(5sqrt(21))/2 i