What are the solutions to the equation λ^2+3λ+2=0 ?

The solutions to the equation λ^2+3λ+2=0 are λ=-1,λ=-2

Find the zeros of λ^2+3λ+2=0

The zeros of λ^2+3λ+2=0 are λ=-1,λ=-2

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λ^{2} + 3 λ + 2 = 0

λ = - 1, λ = - 2

Solution steps

λ^{2} + 3 λ + 2 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

λ_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 3 + 1}{2 \cdot 1}, λ_{2} = \frac{- 3 - 1}{2 \cdot 1}

λ = \frac{- 3 + 1}{2 \cdot 1} : - 1

λ = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

λ = - 1, λ = - 2

145 x^{2} - 118 x + 41 = 0

3 x^{2} - 6 x + 4 = 4

x, x^{2} + y^{2} - 16 x + 2 y + 65 = 0

3 y^{2} - y = 0

- 3 m^{2} - 60 m - 312 = 0

What are the solutions to the equation λ^2+3λ+2=0 ?
The solutions to the equation λ^2+3λ+2=0 are λ=-1,λ=-2
Find the zeros of λ^2+3λ+2=0
The zeros of λ^2+3λ+2=0 are λ=-1,λ=-2