What are the solutions to the equation 120x^2+x-75=0 ?

The solutions to the equation 120x^2+x-75=0 are x=(-1+sqrt(36001))/(240),x=(-1-sqrt(36001))/(240)

Find the zeros of 120x^2+x-75=0

The zeros of 120x^2+x-75=0 are x=(-1+sqrt(36001))/(240),x=(-1-sqrt(36001))/(240)

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120 x^{2} + x - 75 = 0

x = \frac{- 1 + 36001}{240}, x = \frac{- 1 - 36001}{240}

Decimal Notation

x = 0.78641 \dots, x = - 0.79474 \dots

Solution steps

120 x^{2} + x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 120 ( - 75 )}{2 \cdot 120}

1^{2} - 4 \cdot 120 (- 75) = 36001

x_{1, 2} = \frac{- 1 \pm 36001}{2 \cdot 120}

Separate the solutions

x_{1} = \frac{- 1 + 36001}{2 \cdot 120}, x_{2} = \frac{- 1 - 36001}{2 \cdot 120}

x = \frac{- 1 + 36001}{2 \cdot 120} : \frac{- 1 + 36001}{240}

x = \frac{- 1 - 36001}{2 \cdot 120} : \frac{- 1 - 36001}{240}

The solutions to the quadratic equation are:

x = \frac{- 1 + 36001}{240}, x = \frac{- 1 - 36001}{240}

\frac{1}{3} x^{2} - 5 x + 25 = 0

(6 + y)^{2} + y^{2} = 218

2 x^{2} - 4 x - 8 = - x^{2} + x

4 x^{2} + 9 = 73

2 x^{2} + 3 = - 7 x

What are the solutions to the equation 120x^2+x-75=0 ?
The solutions to the equation 120x^2+x-75=0 are x=(-1+sqrt(36001))/(240),x=(-1-sqrt(36001))/(240)
Find the zeros of 120x^2+x-75=0
The zeros of 120x^2+x-75=0 are x=(-1+sqrt(36001))/(240),x=(-1-sqrt(36001))/(240)