What are the solutions to the equation 5x^2-4x=2 ?

The solutions to the equation 5x^2-4x=2 are x=(2+sqrt(14))/5 ,x=(2-sqrt(14))/5

Find the zeros of 5x^2-4x=2

The zeros of 5x^2-4x=2 are x=(2+sqrt(14))/5 ,x=(2-sqrt(14))/5

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5 x^{2} - 4 x = 2

x = \frac{2 + 14}{5}, x = \frac{2 - 14}{5}

Decimal Notation

x = 1.14833 \dots, x = - 0.34833 \dots

Solution steps

5 x^{2} - 4 x = 2

Move

2

to the left side

5 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 2) = 214

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 2 14}{2 \cdot 5}

x = \frac{- ( - 4 ) + 2 14}{2 \cdot 5} : \frac{2 + 14}{5}

x = \frac{- ( - 4 ) - 2 14}{2 \cdot 5} : \frac{2 - 14}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 14}{5}, x = \frac{2 - 14}{5}

27 x^{2} + 9 x + 3 = 0

2 (y - 2)^{2} = 150

2 (x + 3)^{2} - 5 = 14 x + 7

A, A^{2} X - C = B

3 x^{2} + 4 x - 1

What are the solutions to the equation 5x^2-4x=2 ?
The solutions to the equation 5x^2-4x=2 are x=(2+sqrt(14))/5 ,x=(2-sqrt(14))/5
Find the zeros of 5x^2-4x=2
The zeros of 5x^2-4x=2 are x=(2+sqrt(14))/5 ,x=(2-sqrt(14))/5