What are the solutions to the equation t^2-4=12 ?

The solutions to the equation t^2-4=12 are t=4,t=-4

Find the zeros of t^2-4=12

The zeros of t^2-4=12 are t=4,t=-4

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t^{2} - 4 = 12

t = 4, t = - 4

Solution steps

t^{2} - 4 = 12

Move

4

to the right side

t^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 16, t = - 16

16 = 4

- 16 = - 4

t = 4, t = - 4

x, 12 x^{2} - 120 x + 209 = 0

3 x^{2} - 6 x + 1 = 0

m^{2} - 6 m = 0

2 x^{2} - 7 x - 5 = 0

12 x^{2} - 156 x + 360 = 0

What are the solutions to the equation t^2-4=12 ?
The solutions to the equation t^2-4=12 are t=4,t=-4
Find the zeros of t^2-4=12
The zeros of t^2-4=12 are t=4,t=-4