What are the solutions to the equation 3x^2-6+4x^2=15 ?

The solutions to the equation 3x^2-6+4x^2=15 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 3x^2-6+4x^2=15

The zeros of 3x^2-6+4x^2=15 are x=sqrt(3),x=-sqrt(3)

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3 x^{2} - 6 + 4 x^{2} = 15

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

3 x^{2} - 6 + 4 x^{2} = 15

Move

6

to the right side

3 x^{2} + 4 x^{2} = 21

Add similar elements:

3 x^{2} + 4 x^{2} = 7 x^{2}

7 x^{2} = 21

Divide both sides by

7

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

x^{2} - 7 x + 10

x, x^{2} + y^{2} + z^{2} - 2 x + 6 y + 8 z + 1 = 0

t^{2} = 50

392 - 6 x^{2} = 0

3 x^{2} + 8 x + 5 = 0

What are the solutions to the equation 3x^2-6+4x^2=15 ?
The solutions to the equation 3x^2-6+4x^2=15 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 3x^2-6+4x^2=15
The zeros of 3x^2-6+4x^2=15 are x=sqrt(3),x=-sqrt(3)