What are the solutions to the equation 2x^2-14x+49=0 ?

The solutions to the equation 2x^2-14x+49=0 are x= 7/2+i 7/2 ,x= 7/2-i 7/2

Find the zeros of 2x^2-14x+49=0

The zeros of 2x^2-14x+49=0 are x= 7/2+i 7/2 ,x= 7/2-i 7/2

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2 x^{2} - 14 x + 49 = 0

x = \frac{7}{2} + i \frac{7}{2}, x = \frac{7}{2} - i \frac{7}{2}

Solution steps

2 x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 49}{2 \cdot 2}

Simplify

(- 14)^{2} - 4 \cdot 2 \cdot 49 : 14 i

x_{1, 2} = \frac{- ( - 14 ) \pm 14 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14 i}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 14 i}{2 \cdot 2}

x = \frac{- ( - 14 ) + 14 i}{2 \cdot 2} : \frac{7}{2} + i \frac{7}{2}

x = \frac{- ( - 14 ) - 14 i}{2 \cdot 2} : \frac{7}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2} + i \frac{7}{2}, x = \frac{7}{2} - i \frac{7}{2}

x^{2} + 14 x + 36 = 0

k^{2} = 9

x^{2} - 25 = 0

- 2 x^{2} + 3 x - 3 = 0

- 6 x^{2} - 8 x - 5 = 0

What are the solutions to the equation 2x^2-14x+49=0 ?
The solutions to the equation 2x^2-14x+49=0 are x= 7/2+i 7/2 ,x= 7/2-i 7/2
Find the zeros of 2x^2-14x+49=0
The zeros of 2x^2-14x+49=0 are x= 7/2+i 7/2 ,x= 7/2-i 7/2