What are the solutions to the equation 49v^2+16=-56v ?

The solutions to the equation 49v^2+16=-56v are v=-4/7

Find the zeros of 49v^2+16=-56v

The zeros of 49v^2+16=-56v are v=-4/7

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49 v^{2} + 16 = - 56 v

v = - \frac{4}{7}

Decimal Notation

v = - 0.57142 \dots

Solution steps

49 v^{2} + 16 = - 56 v

Move

56 v

to the left side

49 v^{2} + 16 + 56 v = 0

Write in the standard form

a x^{2} + b x + c = 0

49 v^{2} + 56 v + 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 49 \cdot 16}{2 \cdot 49}

5 6^{2} - 4 \cdot 49 \cdot 16 = 0

v_{1, 2} = \frac{- 56 \pm 0}{2 \cdot 49}

v = \frac{- 56}{2 \cdot 49}

\frac{- 56}{2 \cdot 49} = - \frac{4}{7}

v = - \frac{4}{7}

The solution to the quadratic equation is:

v = - \frac{4}{7}

0.012 x^{2} - 0.583 x + 35.727 = 40

x^{2} - 2 x + 2 = 2 x - 1

x^{2} = 250

x^{2} = 252

x^{2} = 240

What are the solutions to the equation 49v^2+16=-56v ?
The solutions to the equation 49v^2+16=-56v are v=-4/7
Find the zeros of 49v^2+16=-56v
The zeros of 49v^2+16=-56v are v=-4/7