What are the solutions to the equation m^2+6m+25=0 ?

The solutions to the equation m^2+6m+25=0 are m=-3+4i,m=-3-4i

Find the zeros of m^2+6m+25=0

The zeros of m^2+6m+25=0 are m=-3+4i,m=-3-4i

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m^{2} + 6 m + 25 = 0

m = - 3 + 4 i, m = - 3 - 4 i

Solution steps

m^{2} + 6 m + 25 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

m_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, m_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

m = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

m = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

m = - 3 + 4 i, m = - 3 - 4 i

0 = - x^{2} - x + 2

4 x^{2} + 108 = 0

- 6 x^{2} + 48 x - 42 = 0

g^{2} = 25

x^{2} + x \cdot 1 0^{- 3.2} - 1 0^{- 3.2} \cdot 0.1 = 0

What are the solutions to the equation m^2+6m+25=0 ?
The solutions to the equation m^2+6m+25=0 are m=-3+4i,m=-3-4i
Find the zeros of m^2+6m+25=0
The zeros of m^2+6m+25=0 are m=-3+4i,m=-3-4i