What are the solutions to the equation -5x^2+8x-9=0 ?

The solutions to the equation -5x^2+8x-9=0 are x= 4/5-i(sqrt(29))/5 ,x= 4/5+i(sqrt(29))/5

Find the zeros of -5x^2+8x-9=0

The zeros of -5x^2+8x-9=0 are x= 4/5-i(sqrt(29))/5 ,x= 4/5+i(sqrt(29))/5

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- 5 x^{2} + 8 x - 9 = 0

x = \frac{4}{5} - i \frac{29}{5}, x = \frac{4}{5} + i \frac{29}{5}

Solution steps

- 5 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 5 ) ( - 9 )}{2 ( - 5 )}

Simplify

8^{2} - 4 (- 5) (- 9) : 229 i

x_{1, 2} = \frac{- 8 \pm 2 29 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 29 i}{2 ( - 5 )}, x_{2} = \frac{- 8 - 2 29 i}{2 ( - 5 )}

x = \frac{- 8 + 2 29 i}{2 ( - 5 )} : \frac{4}{5} - i \frac{29}{5}

x = \frac{- 8 - 2 29 i}{2 ( - 5 )} : \frac{4}{5} + i \frac{29}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} - i \frac{29}{5}, x = \frac{4}{5} + i \frac{29}{5}

7 x^{2} + 3 x + 2 = 0

x, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} + \frac{z ^{2}}{9} = 1

x^{2} + (x + 2)^{2} = 452

4 x^{2} - 28 x + 45 = 0

4 x^{2} - 3 x + \frac{9}{16} = 0

What are the solutions to the equation -5x^2+8x-9=0 ?
The solutions to the equation -5x^2+8x-9=0 are x= 4/5-i(sqrt(29))/5 ,x= 4/5+i(sqrt(29))/5
Find the zeros of -5x^2+8x-9=0
The zeros of -5x^2+8x-9=0 are x= 4/5-i(sqrt(29))/5 ,x= 4/5+i(sqrt(29))/5