What are the solutions to the equation 0.022-0.22x-x^2=0 ?

The solutions to the equation 0.022-0.22x-x^2=0 are x=-(11+sqrt(341))/(100),x=(sqrt(341)-11)/(100)

Find the zeros of 0.022-0.22x-x^2=0

The zeros of 0.022-0.22x-x^2=0 are x=-(11+sqrt(341))/(100),x=(sqrt(341)-11)/(100)

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0.022 - 0.22 x - x^{2} = 0

x = - \frac{11 + 341}{100}, x = \frac{341 - 11}{100}

Decimal Notation

x = - 0.29466 \dots, x = 0.07466 \dots

Solution steps

0.022 - 0.22 x - x^{2} = 0

Multiply both sides by

1000

22 - 220 x - 1000 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 1000 x^{2} - 220 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 220 ) \pm ( - 220 ) ^{2} - 4 ( - 1000 ) \cdot 22}{2 ( - 1000 )}

(- 220)^{2} - 4 (- 1000) \cdot 22 = 20341

x_{1, 2} = \frac{- ( - 220 ) \pm 20 341}{2 ( - 1000 )}

Separate the solutions

x_{1} = \frac{- ( - 220 ) + 20 341}{2 ( - 1000 )}, x_{2} = \frac{- ( - 220 ) - 20 341}{2 ( - 1000 )}

x = \frac{- ( - 220 ) + 20 341}{2 ( - 1000 )} : - \frac{11 + 341}{100}

x = \frac{- ( - 220 ) - 20 341}{2 ( - 1000 )} : \frac{341 - 11}{100}

The solutions to the quadratic equation are:

x = - \frac{11 + 341}{100}, x = \frac{341 - 11}{100}

6 n^{2} - 19 n + 10 = 0

x^{2} = \frac{1}{2} (30 - x)^{2}

5 n^{2} - 20 n + 6 = 0

x^{2} + 5 x - 7

x^{2} + 5 x - 1

What are the solutions to the equation 0.022-0.22x-x^2=0 ?
The solutions to the equation 0.022-0.22x-x^2=0 are x=-(11+sqrt(341))/(100),x=(sqrt(341)-11)/(100)
Find the zeros of 0.022-0.22x-x^2=0
The zeros of 0.022-0.22x-x^2=0 are x=-(11+sqrt(341))/(100),x=(sqrt(341)-11)/(100)