What are the solutions to the equation sqrt(3)^2+1^2=x^2 ?

The solutions to the equation sqrt(3)^2+1^2=x^2 are x=2,x=-2

Find the zeros of sqrt(3)^2+1^2=x^2

The zeros of sqrt(3)^2+1^2=x^2 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2} + 1^{2} = x^{2}

x = 2, x = - 2

Solution steps

(3)^{2} + 1^{2} = x^{2}

Switch sides

x^{2} = (3)^{2} + 1^{2}

Simplify

(3)^{2} + 1^{2} : 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

3 x^{2} - 24 x

(x + 2)^{2} = 50

3 x^{2} - 12 x

x^{2} + 5 x - 126 = 0

4 x^{2} - 28 x + 40 = 0

What are the solutions to the equation sqrt(3)^2+1^2=x^2 ?
The solutions to the equation sqrt(3)^2+1^2=x^2 are x=2,x=-2
Find the zeros of sqrt(3)^2+1^2=x^2
The zeros of sqrt(3)^2+1^2=x^2 are x=2,x=-2