What are the solutions to the equation 2n^2-14n+3=3 ?

The solutions to the equation 2n^2-14n+3=3 are n=7,n=0

Find the zeros of 2n^2-14n+3=3

The zeros of 2n^2-14n+3=3 are n=7,n=0

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2 n^{2} - 14 n + 3 = 3

n = 7, n = 0

Solution steps

2 n^{2} - 14 n + 3 = 3

Move

3

to the left side

2 n^{2} - 14 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 0 = 14

n_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 14 ) + 14}{2 \cdot 2}, n_{2} = \frac{- ( - 14 ) - 14}{2 \cdot 2}

n = \frac{- ( - 14 ) + 14}{2 \cdot 2} : 7

n = \frac{- ( - 14 ) - 14}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

n = 7, n = 0

s^{2} + 3 s + 4

x, x^{2} - 3 m x + 2 m^{2} = 0

- 3 x^{2} = 2 x + 5

s^{2} + 9

x^{2} + 14 x = - 49

What are the solutions to the equation 2n^2-14n+3=3 ?
The solutions to the equation 2n^2-14n+3=3 are n=7,n=0
Find the zeros of 2n^2-14n+3=3
The zeros of 2n^2-14n+3=3 are n=7,n=0