What are the solutions to the equation x^2+40=10x ?

The solutions to the equation x^2+40=10x are x=5+sqrt(15)i,x=5-sqrt(15)i

Find the zeros of x^2+40=10x

The zeros of x^2+40=10x are x=5+sqrt(15)i,x=5-sqrt(15)i

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x^{2} + 40 = 10 x

x = 5 + 15 i, x = 5 - 15 i

Solution steps

x^{2} + 40 = 10 x

Move

10 x

to the left side

x^{2} + 40 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 40 : 215 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 15 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 15 i}{2 \cdot 1} : 5 + 15 i

x = \frac{- ( - 10 ) - 2 15 i}{2 \cdot 1} : 5 - 15 i

The solutions to the quadratic equation are:

x = 5 + 15 i, x = 5 - 15 i

3 v^{2} - 12 v = 0

4 = y^{2}

x, 36 x^{2} + 9 y^{2} + 4 z^{2} = 36

t^{2} - 2 t + 10 = 0

7 x^{2} + x = 6

What are the solutions to the equation x^2+40=10x ?
The solutions to the equation x^2+40=10x are x=5+sqrt(15)i,x=5-sqrt(15)i
Find the zeros of x^2+40=10x
The zeros of x^2+40=10x are x=5+sqrt(15)i,x=5-sqrt(15)i