What are the solutions to the equation 2=2x^2+5x-13 ?

The solutions to the equation 2=2x^2+5x-13 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4

Find the zeros of 2=2x^2+5x-13

The zeros of 2=2x^2+5x-13 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 = 2 x^{2} + 5 x - 13

x = \frac{- 5 + 145}{4}, x = \frac{- 5 - 145}{4}

Decimal Notation

x = 1.76039 \dots, x = - 4.26039 \dots

Solution steps

2 = 2 x^{2} + 5 x - 13

Switch sides

2 x^{2} + 5 x - 13 = 2

Move

2

to the left side

2 x^{2} + 5 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 15) = 145

x_{1, 2} = \frac{- 5 \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 145}{2 \cdot 2}, x_{2} = \frac{- 5 - 145}{2 \cdot 2}

x = \frac{- 5 + 145}{2 \cdot 2} : \frac{- 5 + 145}{4}

x = \frac{- 5 - 145}{2 \cdot 2} : \frac{- 5 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 145}{4}, x = \frac{- 5 - 145}{4}

x^{2} - 11 x + 22 = 0

3 x^{2} + 6 x + 7

3 x^{2} + 6 x + 4

x, k x^{2} + 3 k x + 6 = 0

x (x + 7) = x + 7

What are the solutions to the equation 2=2x^2+5x-13 ?
The solutions to the equation 2=2x^2+5x-13 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4
Find the zeros of 2=2x^2+5x-13
The zeros of 2=2x^2+5x-13 are x=(-5+sqrt(145))/4 ,x=(-5-sqrt(145))/4