What are the solutions to the equation (3x^2)/2+4x-2/3 =0 ?

The solutions to the equation (3x^2)/2+4x-2/3 =0 are x=(2(sqrt(5)-2))/3 ,x=-(2(2+sqrt(5)))/3

Find the zeros of (3x^2)/2+4x-2/3 =0

The zeros of (3x^2)/2+4x-2/3 =0 are x=(2(sqrt(5)-2))/3 ,x=-(2(2+sqrt(5)))/3

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\frac{3 x ^{2}}{2} + 4 x - \frac{2}{3} = 0

x = \frac{2 ( 5 - 2 )}{3}, x = - \frac{2 ( 2 + 5 )}{3}

Decimal Notation

x = 0.15737 \dots, x = - 2.82404 \dots

Solution steps

\frac{3 x ^{2}}{2} + 4 x - \frac{2}{3} = 0

Find Least Common Multiplier of

2, 3 : 6

Multiply by LCM=

6

\frac{3 x ^{2}}{2} \cdot 6 + 4 x \cdot 6 - \frac{2}{3} \cdot 6 = 0 \cdot 6

Simplify

9 x^{2} + 24 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 (- 4) = 125

x_{1, 2} = \frac{- 24 \pm 12 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 12 5}{2 \cdot 9}, x_{2} = \frac{- 24 - 12 5}{2 \cdot 9}

x = \frac{- 24 + 12 5}{2 \cdot 9} : \frac{2 ( 5 - 2 )}{3}

x = \frac{- 24 - 12 5}{2 \cdot 9} : - \frac{2 ( 2 + 5 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 5 - 2 )}{3}, x = - \frac{2 ( 2 + 5 )}{3}

18 x^{2} - 16 x - 8 = - 16 x

x^{2} + 3 x - 26 = 0

d^{2} - 2 = 0

y, f = x^{4} y - 2 x^{3} y^{2}

4.9 t^{2} + 9 t + 3 = 0

What are the solutions to the equation (3x^2)/2+4x-2/3 =0 ?
The solutions to the equation (3x^2)/2+4x-2/3 =0 are x=(2(sqrt(5)-2))/3 ,x=-(2(2+sqrt(5)))/3
Find the zeros of (3x^2)/2+4x-2/3 =0
The zeros of (3x^2)/2+4x-2/3 =0 are x=(2(sqrt(5)-2))/3 ,x=-(2(2+sqrt(5)))/3