What are the solutions to the equation x(x+3)=-2 ?

The solutions to the equation x(x+3)=-2 are x=-1,x=-2

Find the zeros of x(x+3)=-2

The zeros of x(x+3)=-2 are x=-1,x=-2

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x (x + 3) = - 2

x = - 1, x = - 2

Solution steps

x (x + 3) = - 2

Expand

x (x + 3) : x^{2} + 3 x

x^{2} + 3 x = - 2

Move

2

to the left side

x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 1}, x_{2} = \frac{- 3 - 1}{2 \cdot 1}

x = \frac{- 3 + 1}{2 \cdot 1} : - 1

x = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

3 x^{2} + 12 + 1 = 0

x^{2} + x - 56 = 0

- 144 + 7 x + x^{2} = 0

9 - \frac{x ^{2}}{3} = 0

k^{2} + 15 k + 56 = 0

What are the solutions to the equation x(x+3)=-2 ?
The solutions to the equation x(x+3)=-2 are x=-1,x=-2
Find the zeros of x(x+3)=-2
The zeros of x(x+3)=-2 are x=-1,x=-2