What are the solutions to the equation -x(5x+12)=-3x^2 ?

The solutions to the equation -x(5x+12)=-3x^2 are x=0,x=-6

Find the zeros of -x(5x+12)=-3x^2

The zeros of -x(5x+12)=-3x^2 are x=0,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x (5 x + 12) = - 3 x^{2}

x = 0, x = - 6

Solution steps

- x (5 x + 12) = - 3 x^{2}

Move

3 x^{2}

to the left side

- x (5 x + 12) + 3 x^{2} = 0

Factor

- x (5 x + 12) + 3 x^{2} : - 2 x (x + 6)

- 2 x (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

- 9 X - 16 = - 5 X - 12

(x - 8)^{2} = - 25

5 y - 10 = 90

16 x^{2} - 64

3 x^{2} - 5 x - 8

What are the solutions to the equation -x(5x+12)=-3x^2 ?
The solutions to the equation -x(5x+12)=-3x^2 are x=0,x=-6
Find the zeros of -x(5x+12)=-3x^2
The zeros of -x(5x+12)=-3x^2 are x=0,x=-6