What are the solutions to the equation -3x^2+12x-7=0 ?

The solutions to the equation -3x^2+12x-7=0 are x=(6-sqrt(15))/3 ,x=(6+sqrt(15))/3

Find the zeros of -3x^2+12x-7=0

The zeros of -3x^2+12x-7=0 are x=(6-sqrt(15))/3 ,x=(6+sqrt(15))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 12 x - 7 = 0

x = \frac{6 - 15}{3}, x = \frac{6 + 15}{3}

Decimal Notation

x = 0.70900 \dots, x = 3.29099 \dots

Solution steps

- 3 x^{2} + 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 7 )}{2 ( - 3 )}

1 2^{2} - 4 (- 3) (- 7) = 215

x_{1, 2} = \frac{- 12 \pm 2 15}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 15}{2 ( - 3 )}, x_{2} = \frac{- 12 - 2 15}{2 ( - 3 )}

x = \frac{- 12 + 2 15}{2 ( - 3 )} : \frac{6 - 15}{3}

x = \frac{- 12 - 2 15}{2 ( - 3 )} : \frac{6 + 15}{3}

The solutions to the quadratic equation are:

x = \frac{6 - 15}{3}, x = \frac{6 + 15}{3}

x^{2} - 2 x + 1 = 50

3 x^{2} + 114 = - 42 x

5 + 7 + 9 + (2 n + 3) = n (n + 4)

v^{2} = - 19 v

0 = x^{2} + 16 x + 64

What are the solutions to the equation -3x^2+12x-7=0 ?
The solutions to the equation -3x^2+12x-7=0 are x=(6-sqrt(15))/3 ,x=(6+sqrt(15))/3
Find the zeros of -3x^2+12x-7=0
The zeros of -3x^2+12x-7=0 are x=(6-sqrt(15))/3 ,x=(6+sqrt(15))/3