What are the solutions to the equation 8x^2-2x-21=0 ?

The solutions to the equation 8x^2-2x-21=0 are x= 7/4 ,x=-3/2

Find the zeros of 8x^2-2x-21=0

The zeros of 8x^2-2x-21=0 are x= 7/4 ,x=-3/2

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8 x^{2} - 2 x - 21 = 0

x = \frac{7}{4}, x = - \frac{3}{2}

Decimal Notation

x = 1.75, x = - 1.5

Solution steps

8 x^{2} - 2 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 21 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 21) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 26}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 26}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 26}{2 \cdot 8}

x = \frac{- ( - 2 ) + 26}{2 \cdot 8} : \frac{7}{4}

x = \frac{- ( - 2 ) - 26}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{3}{2}

a, a^{5} + b^{5} = (a + b) (a^{4} - a^{3} b + a^{2} b^{2} - a b^{3} + b^{4})

q, \frac{1}{4} q^{2} + r = p

6 x^{2} + 17 x - 3 = 0

a^{2} + 1 3^{2} = 1 2^{2}

6 x^{2} + 5 x

What are the solutions to the equation 8x^2-2x-21=0 ?
The solutions to the equation 8x^2-2x-21=0 are x= 7/4 ,x=-3/2
Find the zeros of 8x^2-2x-21=0
The zeros of 8x^2-2x-21=0 are x= 7/4 ,x=-3/2